x^2/3-4x^1/3+3=0

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Solution for x^2/3-4x^1/3+3=0 equation: 


x in (-oo:+oo)

(x^2)/3-((4*x^1)/3)+3 = 0

(x^2)/3+(-4/3)*x+3 = 0

1/3*x^2-4/3*x+3 = 0

DELTA = (-4/3)^2-(1/3*3*4)

DELTA = -20/9

DELTA < 0

x belongs to the empty set

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